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Simplified poker


slapdash

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Two people play. They each put an ante of $10 in the pot. Then they are each "dealt" a random number between 0 and 1. (Assume the numbers will always be different, so you don't need to worry about split pots.) Player A can then check, or bet another $10. If he checks, player B doesn't get a chance to bet. They just compare numbers and the higher number wins the pot of $20. If player A bets, then player B can fold or call (not raise). If he folds, then player A takes the $30 in the pot. If he calls, they compare numbers and the higher number takes the $40 in the pot. Player B's best strategy, assuming he knows what strategy player A is following, is easy to work out. When player A bets, he's giving player B pot odds of 3/1. So player B should call if he has at least a 25% chance of winning; i.e., if his number is bigger than at least a quarter of the numbers player A would have bet with. What about player A? Obviously he can break even on average by always checking. But can he do better? And how?

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Re: Simplified poker Interesting........ Gut feel is player A should raise anything above average (0.5) ..... but I suspect the answer is a bit more complicated than that ...... Will give this some real thought later :ok

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