double result - odds

[paparainbow]

lets say someone has priced the 3way full time final (%) and the 2way halftime final (%) how can we calculate the double result odds? mathematically speaking the outcomes are not independent, hence you cannot just multiply them. any good ideas?

[Guest Ledu]

Re: double result - odds I'm not sure if I undertood your point but: example: 1X2 = odd = % 1 = 1,60 = 63% X = 3,30 = 30% 2 = 2,10 = 48% Double Chance: 1X = 93% = 1,08 2X = 78% = 1,28