Guest przeszczepan Posted January 18, 2004 Share Posted January 18, 2004 Hello, I was wondering if it's possible to calculate "fair odds" on -0,75 AH if you know the line for -0,5 and -1. It looks much easier for -0,25 since you don't have "half win scenario": a-odds on 0:0 AH b-odds on -0,5 AH x odds on -0,25 AH If you win (both handicaps covered) you get the same as if you had bet 0,5 of your stake on 0:0 AH and 0,5 on -0,5 AH: a*0,5 0,5*b-1=x*1-1 x=(a b)/2 If you "half lose" your result is always -0,5 (independent on the odds). If you lose, you lose everything. The first part looks the same for -0,75 but in the "half win" scenario things are getting a little bit more complex: In case my team wins by one goal, I get 0,5*"odds on -0,5 AH" minus 0,5 (half refund-whole stake). It's exactly the same when I take -0,75 AH except for the fact that this time I put odds on -0,75 in the equation so all I learn is that odds on -0,5 and -0,75 should be equal, which is as obvious bullshit as you get. Could anybody help me with that problem, please? Lucas Quote Link to comment Share on other sites More sharing options...
Guest przeszczepan Posted January 18, 2004 Share Posted January 18, 2004 answer Answering own questions may be a syndrome of some kind of mental disorder but, believe it or not, it was the very first thing I thougt of after waking up in the morning. If one team is -0,75, their opponents are +0,75, which is a potential "half lose" sittuation. So it's easy to count the odds for them and than convert them for the "-0,75 team". Sorry for the mess:o . Lucas Quote Link to comment Share on other sites More sharing options...
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